Mechanics11/Seite5/Loesung2.10
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< Mechanics11 | Seite5
a)parabel:
y = k*x2
y = 0.5*x2
x(t) = 0.5*a*t2
a = 1[math]\frac{m}{s^2}[/math]
Bsp: x(4s) = 0.5 * 1[math]\frac{m}{s^2}[/math] * (4s)2 = 8m
0 < t < 4s : x(t) = 0.5 * 1[math]\frac{m}{s^2}[/math] * t2
gerade:
y = m*x + t
v = [math]\frac{\Delta x}{\Delta y}[/math]
[math]\Delta x[/math] = 0,8m
[math]\Delta t[/math] = 0,2s
=> v = [math]\frac{0,8m}{0,2m}[/math] = 4[math]\frac{m}{s}[/math]
v = [math]\frac{3,2m}{0,8s}[/math] = 4[math]\frac{m}{s}[/math]
x(t) = x0 + v*t