Mechanics11/Seite10/Loesung3.14

Lösung zu 3.14:

a) ges: x

  geg: t1 = 6,024 s 

  Lsg: xB1 = 1/2 * a * ( Δt )2

       xB1 = 1/2 * 9,81 N/kg * ( 6,024 s )2 = 177,995 m

       xB1 = 178m

b) geg: v_s = 340 m/s , x_B1 = 178 m

  ges: t2

  Lsg: v = Δx / Δt

       t2 = [math]\frac{178 m}{340 m/s}[/math] = 0,524 s

c) ges: x_B2

  geg: t1 - t2 = 5,5 s

  Lsg: x = 1/2 * 9,81 N/kg * ( 5,5 s )2 = 148,38 m
       xB2 = 148 m

--Franzi-frasiM11 12:13, 16 February 2009 (UTC)