User:Marcosm11

Greetings, my name is Marco and I go currently to the Gisela-Gymnasium in munich. This page is about physics, yay!

Lösung zu 1.6 "Wettflug"

x(t)=x₀+v* [math]\delta {t}[/math]
Bussard:x(t)=14km+95 [math]\frac {km}{h}[/math]* [math]\delta {t}[/math]
Falke:x(t)=0km+153 [math]\frac {km}{h}[/math]* [math]\delta {t}[/math]
Gleichgesetzt:14km+95 [math]\frac {km}{h}[/math]* [math]\delta {t}[/math]=0km+153 [math]\frac {km}{h}[/math]* [math]\delta {t}[/math]

a)

x(t)= x0+ Δt * v x(tF)= 14km+ 95km/h * Δt x(tB)= 0km+ 153km/h * Δt

x(tF)=x(tB) 14km + 95km/h * Δt= 153km/h * Δt 14km = 58km/h * Δt 0,24h=Δt 14min= Δt

b) x(0,24h) = 153km/h * 0,24h x(0,24h)= 36,7km x(14min)= 37 km

c) Der Falke überholt den Bussard bei 37 Kilometern.

Lösung zu 2.7 "Von Null auf Hundert"

geg: v(t) = 100 km/h ; t = 3,87s

ges: a ; x(t)

[math]a=\frac{v(t)}{t}=\frac{100\frac{km}{h}}{3,87s}= \frac{2,8\frac{m}{s}}{3.87s}=7.12\frac{m}{s^2}[/math]

[math]x(t)=\frac{1}{2}*a*t^2=\frac{1}{2}*7.12\frac{m}{s^2}*(3,87s)^2=53,75m[/math]

Lösung zu 3.20

geg m = 35t= 35000kg ; Steigung = 10% ; x = 200m ; v = 50 km/h ; µ = 0.15

a)

ges a

lsg v²=2ax µµµµµµµµµ

[math]a=\frac{v^2}{2*x}[/math]

[math]a=\frac{50^2}{2*200}=6.25\frac{m}{s^2}[/math]

b)

ges F_Motor

lsg [math]F_G=35000kg*9.81\frac{N}{kg}[/math]

[math]F_H=F_G*sin alpha[/math]

F_Motor=F_R+F_H+F_a

F_Motor=F_N+m*a+F_H

F_Motor