Mechanics11/Seite11/Loesung4.3

a)

[math]D = \frac {F}{s}[/math]

[math]D = \frac {50N}{0,80m}[/math]

[math]D = 62,5 \frac {N}{m}[/math]

[math]W_sp = \frac {1}{2} * D * s^2[/math]

[math]W_sp = \frac {1}{2} * 62,5 \frac {N}{m} * 0,80m^2 = 20 J [/math]

b)

[math]W_sp = \frac {1}{2} * 62,5 \frac {N}{m} * 1,30m^2 = 52,8 J[/math]

52,8J - 20J = 32,8J

c)

[math]E = W_gesp.[/math]

=> E = 52,8J

-Marc Schuster, Sebastian Felsner, Maximilan Vrecko-

Zusätzliche Schülerlösung

geg.:

• F = 50 N
• s = 80 cm

ges.:

• D
• W_Sp

a)

[math]D = \frac{F}{s}[/math]

[math]D = \frac{50 N}{0,8 m}[/math]

[math]D = 62,5 \frac{N}{m}[/math]

[math]W_Sp = \frac{1}{2} D * s^2[/math]

[math]W_Sp1 = \frac{1}{2} 62,5 \frac{N}{m} * (0,8 m)^2[/math]

[math]W_Sp1 = 20 J \frac{}{}[/math]

b)

geg.: s_2 = 50 cm + 80 cm = 1,3 m

ges.: W_Sp2

[math]W_Sp2 = \frac{1}{2} 62,5 \frac{N}{m} * (1,3 m)^2 - W_Sp1[/math]

[math]W_Sp2 = 52,8 J - 20 J = 32,8 J \frac{}{}[/math]

c)

ges.: F

[math]F = D * s \frac{}{}[/math]

[math]F = 62,5 \frac{N}{m} * 1,3 m[/math]

[math]F = 1,3 N \frac{}{}[/math]

--FatF 12:07, 25 January 2008 (CET)