Mechanics11/Seite11/Loesung4.1

c) geg: m = 35t = 35000kg t = 40s v = 50kmh^-1 = 13.8ms^-1

  ges: W_besch

  Lsg: W_besch =0.5*m*v²

       W_besch = 0.5*m*v²

       W_besch= 0.5*(35000kg)*(13.8ms^-1)²

       W_besch= 3332700J

d) geg: m = 35t = 35000kg t = 40s v = 50kmh^-1 = 13.8ms^-1

  ges:  P
  Lsg:  P = [math]\frac{W}{t}[/math]
        P = [math]\frac{3332700J}{40s}[/math]
        P = 83317.5W = 83.3175kW = 83kW

--Klaksa 13:06, 25 January 2008 (CET) Ich bedanke mich bei meiner Banknachbarin, durch die mir das Lösen der Aufgabe ermöglicht wurde...

c) m = 35t = 35000kg

t = 40s

v = 50kmh^-1 = 13.8ms^-1

W_a = 0.5*m*v² = 0.5*(35000kg)*(13.8ms^-1)² = 3332700J

d) P = [math]\frac{W}{t}[/math] = [math]\frac{3332700J}{40s}[/math] = 83317.5W = 83.3175kW

--Anki 13:11, 25 January 2008 (CET)

4.2 Brummi

m=35t =3500 kg steigung =10%

konstante beschleunigung nach 200 m =>v =50 km/h

a)v^2 = 2 a x

=> a=v^2/2x =13,8m/s/

[math]\frac{13,8 m/s}{2*200m}[/math]

--Valerie 13:05, 1 February 2008 (CET)

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